JavaScript综合练习3

2026/9/20 16:17:09 拓冰建站浏览量

JavaScript 综合练习 3

1. 案例演示

QQ录屏20240207211159 -original-original

2. 代码实现

<!DOCTYPE html>
<html lang="en"><head><meta charset="UTF-8" /><meta http-equiv="X-UA-Compatible" content="IE=edge" /><meta name="viewport" content="width=device-width, initial-scale=1.0" /><title>js综合案例3</title></head><body><input type="text" id="input" /><ul id="list"></ul><script>const array = [{name: "张三",id: 1001,},{name: "李四",id: 1002,},{name: "王五",id: 1003,},{name: "狗蛋",id: 1004,},];// 获取到list对象const list = document.getElementById("list");// 获取到input对象const input = document.getElementById("input");// 删除list下面所有的元素const removeAllChild = () => {const lis = document.querySelectorAll("li");if (lis.length) {// 循环伪数组，删除list下面所有的元素for (let i = 0; i < lis.length; i++) {list.removeChild(lis[i]);}}};// 重新渲染ul listconst renderList = (array) => {// 先清空list下面的元素removeAllChild();// 将array中的数据添加到列表中for (let i = 0; i < array.length; i++) {const item = array[i];console.log(item);const li = document.createElement("li");li.innerHTML = item.name;list.appendChild(li);}};renderList(array);// 监听input按键事件，当按下回车键的时候,通过输入的id值，找到数组中对应的下标，然后调用splice方法，删除数组中对应的项目input.onkeydown = (e) => {if (e.keyCode === 13) {// input当中的数据const value = Number(e.target.value);// 找到id为value的数据下标 findIndex暂时看不懂，没关系const targetIndex = array.findIndex((item) => {return item.id === value;});if (targetIndex >= 0) {array.splice(targetIndex, 1);renderList(array);}}};</script></body>
</html>

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JavaScript综合练习3

JavaScript 综合练习 3

1. 案例演示

2. 代码实现