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C语言实现简单的扫雷游戏

2026/8/5 6:24:43 拓冰建站 浏览量
C语言实现简单的扫雷游戏

目录

1 -> test.c

2 -> game.c

3 -> game.h



1 -> test.c

#define _CRT_SECURE_NO_WARNINGS 1#include "game.h"void menu()
{printf("************************************\n");printf("*********       1.play      ********\n");printf("*********       0.exit      ********\n");printf("************************************\n");
}void game()
{//show数组为排查出的雷的信息char show[ROWS][COLS] = { 0 };//mine数组为布置好的雷的信息char mine[ROWS][COLS] = { 0 };//初始化棋盘InitBoard(show, ROWS, COLS, '*');InitBoard(mine, ROWS, COLS, '0');//打印棋盘DisplayBoard(show, ROW, COL);//布置雷SetMine(mine, ROW, COL);//DisplayBoard(mine, ROW, COL);//排查雷FineMine(mine, show, ROW, COL);
}int main()
{int input = 0;srand((unsigned int)time(NULL));do{menu();printf("请选择:>");scanf("%d", &input);switch (input){case 1:game();break;case 0:printf("退出游戏\n");break;default:printf("输入错误,请重新输入。\n");break;}} while (input);return 0;
}

2 -> game.c

#define _CRT_SECURE_NO_WARNINGS 1#include "game.h"//初始化棋盘
void InitBoard(char board[ROWS][ROWS], int rows, int cols, char set)
{memset(&board[0][0], set, rows * cols * sizeof(board[0][0]));
}//打印棋盘
void DisplayBoard(char board[ROWS][ROWS], int row, int col)
{printf("******  扫雷  ******\n");for (int j = 0; j <= col; j++){printf("%d ", j);}printf("\n");for (int i = 1; i <= row; i++){printf("%d ", i);for (int j = 1; j <= col; j++){printf("%c ", board[i][j]);}printf("\n");}
}//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
{int cnt = EASY_COUNT;while (cnt){int x = rand() % row + 1;int y = rand() % col + 1;if (mine[x][y] == '0'){mine[x][y] = '1';cnt--;}}
}//计算周围雷的数量
int GetMineCount(char mine[ROWS][COLS], int x, int y)
{return (mine[x - 1][y - 1] +mine[x - 1][y] +mine[x - 1][y + 1] +mine[x][y - 1] +mine[x][y + 1] +mine[x + 1][y - 1] +mine[x + 1][y] +mine[x + 1][y + 1] - 8 * '0');
}//排查雷
void FineMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{int x = 0;int y = 0;int win = 0;while (win < row * col - EASY_COUNT){printf("请输入坐标:>");scanf("%d %d", &x, &y);if (x >= 1 && x <= row && y >= 1 && y <= col){if (mine[x][y] == '1'){printf("很遗憾,排雷失败。\n");DisplayBoard(mine, ROW, COL);break;}else{int cnt = GetMineCount(mine, x, y);show[x][y] = cnt + '0';DisplayBoard(show, ROW, COL);win++;}}else{printf("坐标输入错误,请重新输入\n");}}if (win == row * col - EASY_COUNT){printf("恭喜你排雷成功!!!\n");}
}

3 -> game.h

#pragma once#include <stdio.h>
#include <stdlib.h>
#include <time.h>//棋盘大小
#define ROW 9
#define COL 9
#define ROWS ROW + 2
#define COLS COL + 2
//雷的个数
#define EASY_COUNT 10//初始化棋盘
void InitBoard(char board[ROWS][ROWS], int rows, int cols, char set);//打印棋盘
void DisplayBoard(char board[ROWS][ROWS], int row, int col);//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col);//计算周围雷的数量
int GetMineCount(char mine[ROWS][COLS], int x, int y);//排查雷
void FineMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

代码里的注释感觉已经很清楚啦,就不多讲解啦

感谢各位大佬的支持!!!