ARTICLE DETAIL

建站实战干货

来自一线的建站与推广经验沉淀,每一条都经过真实交付验证。

LeetCode1109. Corporate Flight Bookings

2026/9/14 15:36:16 拓冰建站 浏览量
LeetCode1109. Corporate Flight Bookings

文章目录

    • 一、题目
    • 二、题解

一、题目

There are n flights that are labeled from 1 to n.

You are given an array of flight bookings bookings, where bookings[i] = [firsti, lasti, seatsi] represents a booking for flights firsti through lasti (inclusive) with seatsi seats reserved for each flight in the range.

Return an array answer of length n, where answer[i] is the total number of seats reserved for flight i.

Example 1:

Input: bookings = [[1,2,10],[2,3,20],[2,5,25]], n = 5
Output: [10,55,45,25,25]
Explanation:
Flight labels: 1 2 3 4 5
Booking 1 reserved: 10 10
Booking 2 reserved: 20 20
Booking 3 reserved: 25 25 25 25
Total seats: 10 55 45 25 25
Hence, answer = [10,55,45,25,25]
Example 2:

Input: bookings = [[1,2,10],[2,2,15]], n = 2
Output: [10,25]
Explanation:
Flight labels: 1 2
Booking 1 reserved: 10 10
Booking 2 reserved: 15
Total seats: 10 25
Hence, answer = [10,25]

Constraints:

1 <= n <= 2 * 104
1 <= bookings.length <= 2 * 104
bookings[i].length == 3
1 <= firsti <= lasti <= n
1 <= seatsi <= 104

二、题解

class Solution {
public:vector<int> corpFlightBookings(vector<vector<int>>& bookings, int n) {vector<int> cnt(n+2,0);for(auto x:bookings){cnt[x[0]] += x[2];cnt[x[1] + 1] -= x[2];}for(int i = 1;i <= n;i++){cnt[i] += cnt[i-1];}vector<int> res(n,0);for(int i = 0;i < n;i++){res[i] = cnt[i+1];}return res;}
};