JavaScript 数组去重 ES6 方法

方法一

new Set()生成出来的数据是Set数据结构，需要自行转换成对应结构

let array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 2, 3, 3, 3, 9, 8, 9, 's', 'o', 'o'];
Array.from(new Set(array));

方法二

let array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 2, 3, 3, 3, 9, 8, 9, 's', 'o', 'o'];
...new Set(array);或
const a = '12345678971100';
const b = [...new Set(a)].join('');

方法三

使用indexOf() 方法用于在字符串中查找指定子串，并返回第一个匹配项的索引。

let array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 2, 3, 3, 3, 9, 8, 9, 's', 'o', 'o'];let newarr = [];
for (var i = 0; i < array.length; i++) {if (newarr.indexOf(array[i]) == -1) {newarr.push(array[i]);};
};

方法四

let array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 2, 3, 3, 3, 9, 8, 9, 's', 'o', 'o'];let newarr2 = [];
array.sort(); //先将数组排序
for (var i = 0; i < array.length; i++) {if (array[i] !== array[i + 1]) { //判断后一项 是否跟前一项一样 将后一项放入新数组newarr2.push(array[i]);};
};

方法五

let array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 2, 3, 3, 3, 9, 8, 9, 's', 'o', 'o'];var res = [array[0]];
for (var i = 0; i < array.length; i++) {var repeat = false;for (var j = 0; j < res.length; j++) {if (array[i] == res[j]) {repeat = true;break;}}if (!repeat) {res.push(array[i]);}
}

方法六

let array = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 2, 3, 3, 3, 9, 8, 9, 's', 'o', 'o'];var res = [];
var json = {};
for (var i = 0; i < array.length; i++) {if (!json[array[i]]) {res.push(array[i]);json[array[i]] = 1;}
}