hackv.破解You canhackonly if you solved all versions of this problem.arbitraryadj.任意的choose anarbitraryintegermdenotev.表示Here,gcd(x,y)denotesthe greatest common divisor (GCD) of integersxandy.Portaln.大门入口There are also two portals located at positions x and y (xy).respectivelyadv.分别Using operation 1 on the left and right portalsrespectivelyresults in the arrays [O,2,4,O,3,1] and [3,O,4,2,O,1].lexicographicallyadv.字典序地Find thelexicographicallysmallest permutation you can obtain using these operations.lexiconn.字典indicen.索引A permutation a is lexicographically smaller than permutation b if there exists an index i such that ajbj for allindices1≤ji and aibi.optimaladj.最好的In the fourth test case, it isoptimalnot to do any operations.computev.计算you mustcomputea value for one sequenceterminatev.终止If k0,terminateimmediately and return the sequence x.immediately after紧挨着Then, select any index 1≤i≤|x| and insert (xi1)immediately afterthe element xi.inferv.推断but it is not an easy job toinferthe input from the output of the algorithm.separateadj.单独的分开的For each test case, output the length of the shortest sequence on aseparateline.prefixn.前缀x is aprefixof y, but x≠ycorrespondingadj.对应的the array x has a smaller element than thecorrespondingelement in y.productn.乘积Let f(a) denote the number of subarrays∗ of a whoseproductis divisible by 6.divisibleadj.可以整除的Let f(a) denote the number of subarrays∗ of a whose productisdivisibleby 6.palindromen.回文Apalindromeis a string that reads the same backward as forward, for example, strings z, aaa, aba, abccba are palindromes, but strings codeforces, reality, ab are not.positive integer正整数Apositive integerx is a perfect root if there exists an integer y such that y√x.frostingn.糖霜so thefrostingon the cake is unevenunevenadj.不平坦的so the frosting on the cake isunevenlevelv.使平整To quickly solve this issue, Alice will put her knife at some integer height and then sweep the frosting from left to right to make the frostinglevel.bracketn.括号We say that abracketsequence a is better than a bracket sequence b if one of the following holds:arithmeticn.算术∗A regular bracket sequence is a bracket sequence that can be transformed into a correctarithmeticexpression by inserting the characters 1 and between the original characters of the sequence.hourglassn.沙漏Vadimshourglassmeasures s minutes.errandsn.差事However, Vadim needs to leave forerrandsin m minutesproceedsn.收益After this, the gameproceedsto the next turn, or ends if it is the n-th turn.